🎓 Senior Secondary
| CBSE • Chemistry

Solutions

Types of solutions, colligative properties, Raoult's law, osmosis.

1 Lesson 1 MCQ 1 Mnemonic
+40
XP
Available to earn
1
Lesson

Solutions — Lesson

1) Hook — A Fun Real-Life Example

Have you ever noticed how adding just a pinch of salt to boiling water makes it boil faster? Or how sugar dissolves quickly in hot tea but takes longer in cold water? These everyday observations are all about solutions — a fascinating topic that explains how substances mix at the molecular level. Understanding solutions helps not only in the kitchen but also in industries like pharmaceuticals, agriculture, and even the famous Indian sugar industry!

2) Core Concepts — What Are Solutions?

A solution is a homogeneous mixture of two or more substances. It consists of:

  • Solvent: The substance present in the largest amount (usually liquid).
  • Solute: The substance dissolved in the solvent.

Example: In sugar dissolved in water, water is the solvent and sugar is the solute.

Types of Solutions

Type Example State
Gaseous Solution Air (O₂ + N₂) Gas + Gas
Liquid Solution Sugar in Water Solid + Liquid
Solid Solution Brass (Cu + Zn) Solid + Solid

Concentration Terms

Solutions can be described by how much solute is present in a given amount of solvent or solution. Common units include:

Term Definition Example
Molarity (M) Moles of solute per litre of solution 1 M HCl = 1 mole HCl in 1 L solution
Molality (m) Moles of solute per kg of solvent 2 m NaOH = 2 moles NaOH in 1 kg solvent
Mole Fraction (x) Ratio of moles of one component to total moles x_solute = moles solute / total moles
Mass % Mass of solute per 100 g solution 5% NaCl solution = 5 g NaCl in 100 g solution

Solubility and Factors Affecting It

Solubility is the maximum amount of solute that can dissolve in 100 g of solvent at a given temperature.

  • Effect of Temperature: For most solids, solubility increases with temperature (e.g., sugar in water).
  • Effect of Pressure: Mainly affects gases; solubility of gases decreases with increase in temperature but increases with pressure (Henry's Law).

Henry’s Law

At constant temperature, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid.

Henry’s Law Formula:
c = kP

where, c = concentration of dissolved gas, k = Henry’s law constant, P = partial pressure of the gas.

3) Key Formulas / Rules

Molarity (M): M = moles of solute / volume of solution (L)

Molality (m): m = moles of solute / mass of solvent (kg)

Mole Fraction (x): x_solute = moles of solute / total moles of solution

Mass %: Mass % = (mass of solute / mass of solution) × 100

Density (d): d = mass / volume

Relationship between Molarity and Molality:

m = M / [1 - (M × Molar Mass of solute / density)]

Useful when converting between concentration units.

4) Did You Know?

India is one of the largest producers of sugar, and understanding the solubility of sugar in water is crucial for making jaggery and sugar crystals. The solubility of sugar increases with temperature, which is why jaggery makers heat sugarcane juice to concentrate it before crystallization!

5) Exam Tips

  • Units are crucial: Always write units for concentration (mol/L, mol/kg, % w/w, etc.) to avoid losing marks.
  • Know the difference: Molarity depends on solution volume, molality depends on solvent mass — don’t confuse them.
  • Practice conversions: Questions often ask to convert between molarity, molality, mole fraction, and mass %. Use the formulas carefully.
  • Remember Henry’s Law: Questions on gas solubility under pressure changes are common in board exams.
  • Previous Year Question Pattern: Expect numerical problems (2-3 marks) on concentration calculations, solubility, and Henry’s law. Theory questions may ask definitions or explain factors affecting solubility.

Example Question (2023 CBSE):
Calculate the molality of a solution prepared by dissolving 10 g of NaOH in 500 g of water.

Solution:
Moles of NaOH = 10 / 40 = 0.25 mol
Mass of solvent = 500 g = 0.5 kg
Molality, m = 0.25 / 0.5 = 0.5 mol/kg

2
MCQ Practice

Solutions — Mcq

3
Memory Trick

Solutions — Mnemonic

Mnemonic 1: Types of Solutions (Based on Particle Size) 🧪

SMCSmall, Medium, Colossal”

  • SSolution (Particle size < 1 nm)
  • MColloid (Particle size 1 nm to 100 nm)
  • CSuspension (Particle size > 100 nm)

Hindi phrase: “छोटा मच्छर काटे” (Chhota Machhar Kate) – Small mosquito bite = Small particles = Solution

Mnemonic 2: Factors Affecting Solubility 🌡️💨

PTCPressure, Temperature, Composition”

  • P – Pressure (affects gases mainly)
  • T – Temperature (increases solubility of solids usually)
  • C – Composition of solution (like common ion effect)

Hindi rhyme: “P-T-C से समझो, घुलनशीलता का राज़” (PTC se samjho, ghulansheelta ka raaz)

Mnemonic 3: Raoult’s Law Components ⚖️

VMPVapour pressure, Mole fraction, Pure solvent pressure”

  • Vsolution = Xsolvent × Psolvent0
  • Where: X = mole fraction, P0 = vapour pressure of pure solvent

Funny phrase: “Vicky’s Mom’s Pressure” – Remember vapour pressure depends on mole fraction and pure solvent pressure!

Interactive

Mission: Master This Topic!

Reinforce what you learned with fun activities

🎯

Ready to Battle? Test Your Knowledge!

Practice MCQs, build combos, climb the leaderboard!

Start Practice

Loading...

Hey! 🔥 Your 7-day streak is at risk. Complete one quick quest today?

Streak broken? No worries. Recover with bonus XP by completing a quest now.